This is what is known as a "combination" (versus "permutation") since the order in which the 3 people are selected does not matter. If each job were unique, then you would use a permutation (which is always a larger number). The formula for combinations is sample space (factorial) divided by the product of the number being selected (factorial) and the difference of the two (factorial); i.e, 12!/(3!*9!) =220

Grace G.

asked • 01/02/20# binomial distribution

In how many ways can a member of a hiring committee select 3 of 12 job applicants for further consideration?

Follow
•
1

Add comment

More

Report

## 2 Answers By Expert Tutors

Barry M. answered • 01/02/20

Tutor

5
(1)
Professor, CalTech Grad; Many Years Tutoring Math, SAT/ACT Prep, Chem

12!/(9!3!)

= 12 X 11 X 10 / 6

= 220

## Still looking for help? Get the right answer, fast.

Ask a question for free

Get a free answer to a quick problem.

Most questions answered within 4 hours.

#### OR

Find an Online Tutor Now

Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.